What approximate value will come in place of (?)?

​$$16.02 \times\left\{(16.03)^2\right\}^{\frac{1}{4}}+31.96 \times 8.08=? \times 7.43$$​​

Given:

​$$16.02 \times\left\{(16.03)^2\right\}^{\frac{1}{4}}+31.96 \times 8.08=? \times 7.43\\ \ \\16 \times{(16)}^\frac{1}{2}+32 \times 8=? \times 8\\ \ \\16 \times4+32 \times 8=? \times 8\\ \ \\64 + 256=? \times 8\\ \ \\320 = ? \times 8\\ \ \\? = \frac{320}{8}\\ \ \\? = \bf40$$

Thus, correct option is (c).