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    Two pipes can fill a tank in 5 and 6 hours respectively. A third pipe will empty it in 12 hours. If all the pipes are opened, then find the time taken
    Question

    Two pipes can fill a tank in 5 and 6 hours respectively. A third pipe will empty it in 12 hours. If all the pipes are opened, then find the time taken to either fill or empty the tank.

    A.

    Emptied in 92 hours\frac{9}{2}\, hours​​

    B.

    Filled in 3017\frac{30}{17}​ hours

    C.

    Filled in 6017\frac{60}{17}​ hours

    D.

    Filled in 3011\frac{30}{11}​ hours

    Correct option is C

    Given:
    Time taken by Pipe 1 to fill the tank = 5 hours
    Time taken by Pipe 2 to fill the tank = 6 hours
    Time taken by Pipe 3 to empty the tank = 12 hours
    Concept Used:
    The net rate of filling or emptying the tank is determined by summing the rates of all pipes (positive for filling, negative for emptying). The total time is the reciprocal of the net rate.
    Formula Used:
    Net rate=Rate of Pipe 1+Rate of Pipe 2Rate of Pipe 3\text{Net rate} = \text{Rate of Pipe 1} + \text{Rate of Pipe 2} - \text{Rate of Pipe 3}​​
    Time taken=1Net rate\text{Time taken} = \frac{1}{\text{Net rate}}​​
    Solution:
    Rate of Pipe 1 = 15 \frac{1}{5}​ (tank per hour)
    Rate of Pipe 2 = 16\frac{1}{6}​​ (tank per hour)
    Rate of Pipe 3(emptying pipe) = 112-\frac{1}{12}​​ (tank per hour)

    Net rate=15+16112\text{Net rate} = \frac{1}{5} + \frac{1}{6} - \frac{1}{12}​​

    Net rate=1260+1060560=1760 Time taken=11760=6017 hours.\text{Net rate} = \frac{12}{60} + \frac{10}{60} - \frac{5}{60} = \frac{17}{60} \\ \ \\ \text{Time taken} = \frac{1}{\frac{17}{60}} = \frac{60}{17}\, \text{hours}.​​

    Thus, the tank will be filled in approximately 6017 hours.\bf \frac{60}{17} \, \text{hours}.​​

    Alternate Method:
    Using the formula;
    Total work = Efficiency × Total time
    Total work = LCM of 5, 6, 12 = 60

    Efficiency of Pipe 1 = 605\frac{60}{5}​ = 12

    Efficiency of Pipe 2 = 606\frac{60}{6}​ = 10

    Efficiency of Pipe 3 (emptying pipe) = 6012\frac{60}{12}​ = 5
    As, third pipe is emptying pipe;
    Total efficiency of three pipes = 12 + 10 – 5 = 17
    Time taken by three pipe to filled the tank ;
    Time = 6017\frac{60}{17}​ hours

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