Two numbers are in the ratio 2:3. If the second number is 63, find the first number.

Correct option is D

​$$\textbf{Let the two numbers be in the ratio } 2:3. \\\text{Let the numbers be } 2x \text{ and } 3x. \\\text{Given:} \\3x = 63 \\\Rightarrow x = \frac{63}{3} = 21 \\\text{First number} = 2x = 2 \times 21 = 42 \\\text{Therefore, the first number is } \boxed{42}.$$​​