Question

Two masses m1	ext m_1m1​​ and m2	ext m_2m2​​ are connected by a massless spring of spring constant k. The system is free to oscillate along the length of spring. The system oscillates with a frequency:

Accepted Answer

A

Answer

​12πkμ where μ=((m1 m2)/(m1+m))$$\frac{1}{2 \pi}$$ \sqrt{$$\frac{k}{\mu}$$} 	ext { where } \mu=\left(\left($$\mathrm{m}$$_1 $$\mathrm{~m}$$_2ight) /\left($$\mathrm{m}$$_1+$$\mathrm{m}$$ight)ight)2π1​μk​​ where μ=((m1​ m2​)/(m1​+m))​​

Answer

​μk where μ=((m1 m2)/(m1+m2))\sqrt{$$\frac{\mu}{k}$$} 	ext { where } \mu=\left(\left($$\mathrm{m}$$_1 $$\mathrm{~m}$$_2ight) /\left($$\mathrm{m}$$_1+$$\mathrm{m}$$_2ight)ight)kμ​​ where μ=((m1​ m2​)/(m1​+m2​))​​

Answer

​kμ where μ=((m1 m2)/(m1+m2))\sqrt{$$\frac{k}{\mu}$$} 	ext { where } \mu=\left(\left($$\mathrm{m}$$_1 $$\mathrm{~m}$$_2ight) /\left($$\mathrm{m}$$_1+$$\mathrm{m}$$_2ight)ight)μk​​ where μ=((m1​ m2​)/(m1​+m2​))​​

Answer

​12πμk where μ=((m1 m2)/(m1+m2))$$\frac{1}{2 \pi}$$ \sqrt{$$\frac{\mu}{k}$$} 	ext { where } \mu=\left(\left($$\mathrm{m}$$_1 $$\mathrm{~m}$$_2ight) /\left($$\mathrm{m}$$_1+$$\mathrm{m}$$_2ight)ight)2π1​kμ​​ where μ=((m1​ m2​)/(m1​+m2​))​​

Two masses $\text m_1$ and $\text m_2$ are connected by a massless spring of spring constant k. The system is free to oscillate along the length of spring. The system oscillates with a frequency:

$\frac{1}{2 \pi} \sqrt{\frac{k}{\mu}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}\right)\right)$

$\sqrt{\frac{\mu}{k}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)$

$\sqrt{\frac{k}{\mu}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)$

$\frac{1}{2 \pi} \sqrt{\frac{\mu}{k}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)$

Correct option is A

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Two masses m1\text m_1m1​​ and m2\text m_2m2​​ are connected by a massless spring of spring constant k. The system is free to oscillate along the length of spring. The system oscillates with a frequency:

​12πkμ where μ=((m1 m2)/(m1+m))\frac{1}{2 \pi} \sqrt{\frac{k}{\mu}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}\right)\right)2π1​μk​​ where μ=((m1​ m2​)/(m1​+m))​​

​μk where μ=((m1 m2)/(m1+m2))\sqrt{\frac{\mu}{k}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)kμ​​ where μ=((m1​ m2​)/(m1​+m2​))​​

​kμ where μ=((m1 m2)/(m1+m2))\sqrt{\frac{k}{\mu}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)μk​​ where μ=((m1​ m2​)/(m1​+m2​))​​

​12πμk where μ=((m1 m2)/(m1+m2))\frac{1}{2 \pi} \sqrt{\frac{\mu}{k}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)2π1​kμ​​ where μ=((m1​ m2​)/(m1​+m2​))​​

Correct option is A

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Two masses $\text m_1$ and $\text m_2$ are connected by a massless spring of spring constant k. The system is free to oscillate along the length of spring. The system oscillates with a frequency:

$\frac{1}{2 \pi} \sqrt{\frac{k}{\mu}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}\right)\right)$

$\sqrt{\frac{\mu}{k}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)$

$\sqrt{\frac{k}{\mu}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)$

$\frac{1}{2 \pi} \sqrt{\frac{\mu}{k}} \text { where } \mu=\left(\left(\mathrm{m}_1 \mathrm{~m}_2\right) /\left(\mathrm{m}_1+\mathrm{m}_2\right)\right)$