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Two inductively coupled coils have self-inductance L₁=20H and L₂=320H. Find the maximum possible mutual inductance between the coils.
Question

Two inductively coupled coils have self-inductance L₁=20H and L₂=320H. Find the maximum possible mutual inductance between the coils.

A.

80 H

B.

40 H

C.

100 H

D.

10 H

Correct option is A

The maximum possible mutual inductance M between two inductively coupled coils can be calculated using the formula:M=L1L2Given:L1=20 HL2=320 HNow, calculate the maximum possible mutual inductance:M=20×320M=6400M=80 HTherefore, the maximum possible mutual inductance between the coils is 80 H.\text{The maximum possible mutual inductance } M \text{ between two inductively coupled coils can be calculated using the formula:} \\[6pt]M = \sqrt{L_1 L_2} \\[10pt]\text{Given:} \\[4pt]L_1 = 20\,H \\[4pt]L_2 = 320\,H \\[10pt]\text{Now, calculate the maximum possible mutual inductance:} \\[4pt]M = \sqrt{20 \times 320} \\[4pt]M = \sqrt{6400} \\[4pt]M = 80\,H \\[10pt]\text{Therefore, the maximum possible mutual inductance between the coils is } 80\,H.​​

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