Two dice are thrown simultaneously and the sum of the numbers appearing on them is noted. What is the probability that the sum is 12?

Correct option is C

Given:
When 2 dice are thrown at the same time, the overall possible outcomes are
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Total number of possible outcomes when two dice are thrown simultaneously: 6 × 6 = 36
Formula used:
Probability = No of favorable outcome ÷ No of total outcomes
Solution:
We want the sum of the numbers on the two dice to be 12. The only way to get a sum of 12 is if both dice show a 6:
(6,6)
So, there is only 1 favorable outcome
Probability = $$\frac{1}{36}$$​​
The probability that the sum is 12 is;
= $$\frac{1}{36}$$​​