Two concentric circles form a circular path. The inner and outer circumference of the path are $$56\frac{4}{7}$$ m and $$94\frac{2}{7}$$ m respectively. Find the width of the path.​

Correct option is B

Given:

​$$\begin{aligned}& \text { Inner circumference }=56 \frac{4}{7} \mathrm{~m} \\& \text { Outer circumference }=94 \frac{2}{7} \mathrm{~m}\end{aligned}$$ 

Formula used:

Circumference of a circle = 2πr

Width of the path = Outer radius - Inner radius

Solution:

$$\begin{aligned}& 56 \frac{4}{7}=56.5714 \\& 94 \frac{2}{7}=94.2857\end{aligned}$$ 

Inner radius (r₁)

=> 2πr₁= 56.5714

=> r₁= $$\frac{56.5714}{(2π)}$$​​

=> r₁ = 9

Outer radius (r₂)

=> 2πr₂= 94.2857

=> r₂= $$\frac{94.2857}{(2π)}$$​​

=> r₂ = 15

Width of the path

=> r₂- r₁= 15 - 9

=> Width = 6 m

Thus, the correct answer is (B).

​​​