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Two adjacent angles of a parallelogram are such that one is two thirds the other. Find the measure of the smaller angle.
Question

Two adjacent angles of a parallelogram are such that one is two thirds the other. Find the measure of the smaller angle.

A.

18o18^o​​

B.

72o72^o​​

C.

36o36^o​​

D.

108o108^o​​

Correct option is B

Given:

Adjacent angles of parallelogram is like one is two third of other

Formula Used:

Opposite angle in parallelogram are equal

Sum of adjacent angles of a parallelogram is 180o180^o​​

Solution:

Let one angle be x

Then other angle will be:

= 23ofx=2x3\frac{2}{3} of x = \frac{2x}{3}​​

Now x+2x3=180ox + \frac{2x}{3} = 180^o​​

3x+2x3=180o\frac{3x+2x}{3} = 180^o​​

x=108ox= 108^o​​

The other angle =23 of 108o=72o= \frac{2}{3}\ of \ 108^o = 72^o​​

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