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    Two adjacent angles of a parallelogram are such that one is two thirds the other. Find the measure of the smaller angle.
    Question

    Two adjacent angles of a parallelogram are such that one is two thirds the other. Find the measure of the smaller angle.

    A.

    18o18^o​​

    B.

    72o72^o​​

    C.

    36o36^o​​

    D.

    108o108^o​​

    Correct option is B

    Given:

    Adjacent angles of parallelogram is like one is two third of other

    Formula Used:

    Opposite angle in parallelogram are equal

    Sum of adjacent angles of a parallelogram is 180o180^o​​

    Solution:

    Let one angle be x

    Then other angle will be:

    = 23ofx=2x3\frac{2}{3} of x = \frac{2x}{3}​​

    Now x+2x3=180ox + \frac{2x}{3} = 180^o​​

    3x+2x3=180o\frac{3x+2x}{3} = 180^o​​

    x=108ox= 108^o​​

    The other angle =23 of 108o=72o= \frac{2}{3}\ of \ 108^o = 72^o​​

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