Correct option is C
To populate a
32-bit data bus on a 486 system using
30-bit SIMMs (Single Inline Memory Modules), a total of
4 SIMMs are required. Each 30-bit SIMM contributes part of the data path, and multiple SIMMs combine to complete the 32-bit width needed by the system.
Calculation:
1. A
486 system has a
32-bit data bus, meaning it requires memory that matches this width.
2. Each
30-bit SIMM provides 30 bits of data. To reach or exceed 32 bits:
·
(30 x 4) = 120 bits, which satisfies the requirement (with extra data for parity or error checking if needed).
Important Key Points:
1.
SIMMs are older memory modules used in systems like the 486.
2. Combining multiple SIMMs allows systems to match the required data bus width.
3. This approach ensures compatibility with older system architectures.
Knowledge Booster:
·
2 SIMMs: Provide 60 bits, insufficient for a 32-bit data path.
·
3 SIMMs: Provide 90 bits, insufficient for the task.
·
4 SIMMs: Provide 120 bits, fully meeting the requirement.
·
5 SIMMs: Provide more than needed and are unnecessary.