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Three out of four letter clusters are similar in some manner and one is different. Select the odd one out.
Question

Three out of four letter clusters are similar in some manner and one is different.
Select the odd one out.

A.

XAD

B.

QUY

C.

FIL

D.

LOR

Correct option is B

Given: Letter clusters: XAD, QUY, FIL, LOR.

Concept: Alphabetic positional increment series.


Solution:
Check the numerical forward shift between letters in each cluster:
Option A (XAD): X(24) + 3 = A(1, cyclical 27); A(1) + 3 = D(4). Pattern is +3, +3.
Option C (FIL): F(6) + 3 = I(9); I(9) + 3 = L(12). Pattern is +3, +3.
Option D (LOR): L(12) + 3 = O(15); O(15) + 3 = R(18). Pattern is +3, +3.
Option B (QUY): Q(17) + 4 = U(21); U(21) + 4 = Y(25). Pattern is +4, +4.

Because QUY follows a +4 increment while the rest strictly follow a +3 increment, it is the odd one out.

Final Answer: QUY

So the correct answer is (b)

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