Three numbers which are co-prime to each other are such that the product of the first two is 391 and that of the last two is 943. Find the middle number.

Correct option is B

Given:

Product of first two = 391

Product of last two = 943

Formula Used:

Co-prime numbers are number which have one as their common factor or their HCF is 1

Solution:

Let the three numbers are a,b and c

Then a$$\times$$​ b = 391

And b $$\times$$​ c = 943

Both 391 and 943 has b number as common

Hence HCF of 391 and 943 is middle number b

391 = 17 $$\times$$​ 23

943 = 23$$\times$$​ 41

Hence b= 23

The middle number is 23