Three cards are drawn one after another with replacement from a pack of cards. What is the probability of getting first card a Jack, second card a black card, and third card an even numbered card?

Correct option is B

Given:  

Cards are drawn one after another with replacement.

Concept Used:

Concept of Probability;
$$\text{Probability, } P(E) = \frac{\text{Number of favourable outcomes}}{\text{Total number of possible outcomes}}$$​

Where, P(E) = Probability of events,

Solution:

As per the question;

Total number of cards in pack of cards = 52

Total jack cards = 4

Total black cards = 26

Total even number of cards = 20

Now,

probability of getting first card a Jack = $$\frac{4}{52} = \frac{1}{13}$$​

probability of getting second card a black card with replacement = $$\frac{26}{52}=\frac{1}{2}$$​

probability of getting third card an even numbered card = $$\frac{20}{52}=\frac{5}{13}$$​

required probability = $$\frac{1}{13} \times \frac{1}{2} \times \frac{5}{13} = \frac{5}{338}$$​