This question is based on the following words.
TOO CUT JAB AGE
In each of the words, if each vowel is changed to the letter following it in the English alphabetical order and each consonant is changed to the letter preceding it in the English alphabetical order, then how many letter-clusters thus formed will have no vowel in them?

Information Given:
TOO, CUT, JAB, AGE
Rule: Vowel → next letter; Consonant → previous letter.

Step-by-step:
TOO → T→S, O→P, O→P → SPP (no vowel)
CUT → C→B, U→V, T→S → BVS (no vowel)
JAB → J→I, A→B, B→A → IBA (contains vowels)
AGE → A→B, G→F, E→F → BFF (no vowel)

Clusters without vowels: SPP, BVS, BFF → total = 3.

Final Answer:
Three

Final Correct Option:
B