This question is based on the five, three-digit numbers given below.
(Left) 248, 382, 425, 127, 335 (Right)
( Example -697- First digit =6, second digit =9 and third digit =7)
NOTE - All operations to be done from left to right.
If 3 is added to the first digit of every number, in how many numbers will the first digit be exactly divisible by the second digit?

Correct option is A

1.  248 : (2+3) $$\div$$ 4 = $$\frac{5}{4}$$ = completely not divisible
2. 382 : (3+3) $$\div$$8 = $$\frac{6}{8}$$ = completely not divisible
3. 425 : (4+3) $$\div$$ = $$\frac{7}{2}$$ = completely not divisible
4. 127 : (1+3) $$\div$$2 = $$\frac{4}{2}$$ =2 = completely divisible
5. 335 : (3+3)  completely divisible$$\div$$ 3 = $$\frac{6}{3}= 2$$ = completely divisible