This question is based on the five, three-digit numbers given below:
(Left) 158 438 182 325 230 (Right)
If 5 is added to the first digit of every number, in how many numbers will the first digit be exactly divisible by the second digit?

Correct option is A

Solution

Add 5 to the first digit of each number:

1. For 158, first digit = 1. New first digit = 1 + 5 = 6.

2. For 438, first digit = 4. New first digit = 4 + 5 = 9.

3. For 182, first digit = 1. New first digit = 1 + 5 = 6.

4. For 325, first digit = 3. New first digit = 3 + 5 = 8.

5. For 230, first digit = 2. New first digit = 2 + 5 = 7.

Check divisibility of the new first digit by the second digit:

1. For 158 (new: 658): First digit = 6, Second digit = 5. 6 ÷ 5 ≠ 0 (Not divisible).

2. For 438 (new: 938): First digit = 9, Second digit = 3. 9 ÷ 3 = 0 (Divisible).

3. For 182 (new: 682): First digit = 6, Second digit = 8. 6 ÷ 8 ≠ 0 (Not divisible).

4. For 325 (new: 825): First digit = 8, Second digit = 2. 8 ÷ 2 = 0 (Divisible).

5. For 230 (new: 730): First digit = 7, Second digit = 3. 7 ÷ 3 ≠ 0 (Not divisible).

Count the cases where the first digit is divisible by the second digit:

The numbers 438 and 325 satisfy the condition.