Correct option is C
Given:
There are two couples, Meera-Namit and Kavita-Punit.
The sum of the salaries of Meera and Namit is more than the sum of the salaries of Kavita and Punit.
The sum of the salaries of Meera and Kavita is the same as the sum of the salaries of Namit and Punit.
Moreover, Meera earns half as much as the sum of the salaries of Namit and Punit.
From the given information Arrangement will be:
People involved:
Meera, Namit, Kavita. Punit
Let their salaries be:
Meera = M
Namit = N
Kavita = K
Punit = P
1: Meera + Namit > Kavita + Punit
M + N > K + P ...(1)
2: Meera + Kavita = Namit + Punit
M + K = N + P ...(2)
3: Meera = ½ × (Namit + Punit)
M = ½ × (N + P) ...(3)
From (3): Multiply both sides: 2M = N + P ...(4)
Substitute (4) into (2):
From (2): M + K = N + P
But from (4): N + P = 2M
So: M + K = 2M => K = M ...(5)
Now plug into (1):
M + N > K + P
From (5): K = M
So: M + N > M + P => N > P
We know now:
N > P
K = M
N + P = 2M
So N must be greater than both P and M.
Namit's salary is highest
Thus, the correct option is (C) Namit.
Meera, Namit, Kavita. Punit
Let their salaries be:
Meera = M
Namit = N
Kavita = K
Punit = P
1: Meera + Namit > Kavita + Punit
M + N > K + P ...(1)
2: Meera + Kavita = Namit + Punit
M + K = N + P ...(2)
3: Meera = ½ × (Namit + Punit)
M = ½ × (N + P) ...(3)
From (3): Multiply both sides: 2M = N + P ...(4)
Substitute (4) into (2):
From (2): M + K = N + P
But from (4): N + P = 2M
So: M + K = 2M => K = M ...(5)
Now plug into (1):
M + N > K + P
From (5): K = M
So: M + N > M + P => N > P
We know now:
N > P
K = M
N + P = 2M
So N must be greater than both P and M.
Namit's salary is highest
Thus, the correct option is (C) Namit.