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The volume (in cm3 ) of a right circular cone, whose slant height is 28 cm and radius of base is 21 cm, is (Take π = 22/7 )
Question

The volume (in cm3 ) of a right circular cone, whose slant height is 28 cm and radius of base is 21 cm, is (Take π = 22/7 )

A.

​30808

B.

161771617√7​​

C.

32347 3234√7​​

D.

38808

Correct option is C

Given:

Slant height = 28 cm, radius = 21 cm

π=227\pi = \frac{22}{7}​​

Formula Used:

Height=Slant height2Radius2\text{Height} = \sqrt{\text{Slant height}^2 - \text{Radius}^2} 

Volume=13πr2h\text{Volume} = \frac{1}{3} \pi r^2 h 

Solution:

Height: 

h=282212=784441=343h = \sqrt{28^2 - 21^2} = \sqrt{784 - 441} = \sqrt{343}  

Then volume of the cone = 

Volume=13×227×212×343=32347\text{Volume} = \frac{1}{3} \times \frac{22}{7} \times 21^2 \times \sqrt{343} = 3234\sqrt{7}​ cm3  



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