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    ​The voltage equation of a DC long-shunt compound generator is (where Eg is generated
    Question

    The voltage equation of a DC long-shunt compound generator is (where Eg is generated EMF, Vt is terminal voltage, Ia is armature current, Ra is armature resistance, IL is load current, Rse is series resistance, and Vbrush is brush contact drop)\text{The voltage equation of a DC long-shunt compound generator is } \\\text{(where } E_g \text{ is generated EMF, } V_t \text{ is terminal voltage, } I_a \text{ is armature current, } R_a \text{ is armature resistance, } I_L \text{ is load current, } R_{se} \text{ is series resistance, and } V_{\text{brush}} \text{ is brush contact drop)}​​

    A.

    Eg=Vt+IaRaE_g = V_t + I_a R_a​​

    B.

    Eg=VtIaRaE_g = V_t - I_a R_a​​

    C.

    Eg=Vt+Ia(Ra+Rse)+VbrushE_g = V_t + I_a (R_a + R_{se}) + V_{brush}​​

    D.

    Eg=Vt+IaRa+ILRseE_g = V_t + I_a R_a + I_L R_{se}​​

    E.

    Eg=VtIaRaE_g = V_t - \frac{I_a}{R_a}​​

    Correct option is C

    DC Long shunt compound generator

    Eg=Vt+Ia(Ra+Rse)+VbrushE_g = V_t + I_a (R_a + R_{se}) + V_{brush}

    ​​

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