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    The velocity of an object at time t₁ is v₁, and at time t₂, it becomes v₂. The average acceleration of the object in that time-interval is:
    Question

    The velocity of an object at time t₁ is v₁, and at time t₂, it becomes v₂. The average acceleration of the object in that time-interval is:

    A.

    v₂ / (t₂ − t₁)

    B.

    (v₂ − v₁) / (t₂ − t₁)

    C.

    (v₂ − v₁) / t₂

    D.

    v₂ / t₂

    Correct option is B

    The correct answer is: (b) (v₂ − v₁) / (t₂ − t₁)
    Explanation:

    Average acceleration is defined as the change in velocity per unit time.

    Average acceleration=Final velocityInitial velocityFinal timeInitial time=v2v1t2t1\text{Average acceleration} = \frac{\text{Final velocity} - \text{Initial velocity}}{\text{Final time} - \text{Initial time}} = \frac{v_2 - v_1}{t_2 - t_1}​​

    This formula gives the average rate at which an object changes its velocity over the time interval t₁ to t₂. It applies whether the motion is linear or non-linear.

    Information Booster:

    • SI unit of acceleration is m/s²
    • If v₂ > v₁, acceleration is positive; if v₂ < v₁, it's negative (deceleration)
    • Used to analyze uniform or non-uniform motion.​​
    • Constant acceleration implies equal change in velocity per unit time.
    • Acceleration is a vector quantity — direction matters.

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