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The velocity of an object at time t₁ is v₁, and at time t₂, it becomes v₂. The average acceleration of the object in that time-interval is:
Question

The velocity of an object at time t₁ is v₁, and at time t₂, it becomes v₂. The average acceleration of the object in that time-interval is:

A.

v₂ / (t₂ − t₁)

B.

(v₂ − v₁) / (t₂ − t₁)

C.

(v₂ − v₁) / t₂

D.

v₂ / t₂

Correct option is B

The correct answer is: (b) (v₂ − v₁) / (t₂ − t₁)
Explanation:

Average acceleration is defined as the change in velocity per unit time.

Average acceleration=Final velocityInitial velocityFinal timeInitial time=v2v1t2t1\text{Average acceleration} = \frac{\text{Final velocity} - \text{Initial velocity}}{\text{Final time} - \text{Initial time}} = \frac{v_2 - v_1}{t_2 - t_1}​​

This formula gives the average rate at which an object changes its velocity over the time interval t₁ to t₂. It applies whether the motion is linear or non-linear.

Information Booster:

• SI unit of acceleration is m/s²
• If v₂ > v₁, acceleration is positive; if v₂ < v₁, it's negative (deceleration)
• Used to analyze uniform or non-uniform motion.​​
• Constant acceleration implies equal change in velocity per unit time.
• Acceleration is a vector quantity — direction matters.

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