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The variance of a set of value x₁, x₂, …, xnx_nxn is given by which of the following formulae?

Question

The variance of a set of value x₁, x₂, …, $x_n$ is given by which of the following formulae?

$(Σx^2)/n-(Σx/n)^2$

$(Σx^2)/n-Σx/n$

$(Σx/n)^2-(Σx^2)/n$

$(Σx/n)^2$

Solution

Correct option is A

Solution:

The correct formula for the variance of a set of values

x_1, x_2, \dots, x_n

is:

\text{Variance} = \frac{\sum x^2}{n} - \left( \frac{\sum x}{n} \right)^2

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The variance of a set of value x₁, x₂, …, $x_n$ is given by which of the following formulae?

$(Σx^2)/n-(Σx/n)^2$

$(Σx^2)/n-Σx/n$

$(Σx/n)^2-(Σx^2)/n$

$(Σx/n)^2$

Correct option is A

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The variance of a set of value x₁, x₂, …, xnx_nxn​​ is given by which of the following formulae?

​(Σx2)/n−(Σx/n)2(Σx^2)/n-(Σx/n)^2(Σx2)/n−(Σx/n)2​​

​(Σx2)/n−Σx/n(Σx^2)/n-Σx/n(Σx2)/n−Σx/n​​

​(Σx/n)2−(Σx2)/n(Σx/n)^2-(Σx^2)/n(Σx/n)2−(Σx2)/n​​

​(Σx/n)2(Σx/n)^2(Σx/n)2​​

Correct option is A

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The variance of a set of value x₁, x₂, …, $x_n$ is given by which of the following formulae?

$(Σx^2)/n-(Σx/n)^2$

$(Σx^2)/n-Σx/n$

$(Σx/n)^2-(Σx^2)/n$

$(Σx/n)^2$