​$$\text{The value of } 8^3 - 1^2 + \left(\frac{42}{2}\right)^2 - 7 + 4 \times 9 = \, \_\_\_\_$$​​

Correct option is C

Given:

​$$8^3 - 1^2 + \left(\frac{42}{2}\right)^2 - 7 + 4 \times 9$$

Solution:

​$$8^3 - 1^2 + \left(21\right)^2 - 7 + 4 \times 9$$

= 512 - 1 + 441 - 7 + 36

= 989 - 8 = 981