The value of $$√729+√1681+√576-√1849$$​ is:

Correct option is B

Given:

$$\sqrt{729}+\sqrt{1681}+\sqrt{576}-\sqrt{1849}$$​​​​

Formula used:

​$$\sqrt{n} = x \quad \text{such that} \quad x^2 = n$$

Solution:

​$$\sqrt{729} + \sqrt{1681} + \sqrt{576} - \sqrt{1849}$$   

values of : 

$$\sqrt{729} = 27, \quad \sqrt{1681} = 41, \quad \sqrt{576} = 24, \quad \sqrt{1849} = 43$$ 

So, using the values;

= 27 + 41 + 24 - 43

= (27 + 41 + 24) - 43

= 92 - 43

= 49

The value of $$\sqrt{729} + \sqrt{1681} + \sqrt{576} - \sqrt{1849} =\bf 49$$​​