Correct option is D
Given:
68−6×[4+4×12−4(6−5)×3÷15]
Concept Used:
Operation preference wiseBracketsOrders,ofDivisionMultiplicationAdditionSubtractionSymbol[],,()²(power),√(root),of÷×+−
Solution:
68 - 6 × [ 4 + 4 × {12 - 4 ( 6 - 5 ) × 3} ÷ 15] \\
= 68 - 6 × [ 4 + 4 × {12 - 4 \times 1 × 3} ÷ 15] \\
= 68 - 6 × [ 4 + 4 × {12 - 12} ÷ 15] \\
= 68 - 6 × [ 4 + 4 × 0 ÷ 15] \\
= 68 - 6 × [ 4 ] \\
= 68 - 24\\
= 44\\