The value of $$4^2-3(8)^{\frac23}+\left(\frac{16}9\right)^{\frac12}$$​is:

Correct option is D

Given: 

​$$4^2-3(8)^{\frac23}+\left(\frac{16}9\right)^{\frac12}$$ 

Solution: ​

​$$4^2-3(8)^{\frac23}+\left(\frac{16}9\right)^{\frac12} \\ \ \\ = 16-3(4)+\frac{4}3 \\ \ \\ = 16-12+\frac{4}3 \\ \ \\ =\frac{12+4}{3} \\ \ \\ = \frac{16}{3} = 5\frac13$$​​