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The value of [(34.45)]2−(11.75)2]×5.15[(25.75)2+(25.75×20.45)]×22.7\frac{[(34.45)]^2-(11.75)^2]×5.15}{[(25.75)^2+(25.75×20.45)]×22.7}[(25.75)2+(2
Question

The value of [(34.45)]2(11.75)2]×5.15[(25.75)2+(25.75×20.45)]×22.7\frac{[(34.45)]^2-(11.75)^2]×5.15}{[(25.75)^2+(25.75×20.45)]×22.7}​ is:

A.

15\frac{1}{5}​​

B.

12\frac{1}{2}​​

C.

23\frac{2}{3}​​

D.

110\frac{1}{10}​​

Correct option is A

Given:

[(34.45)2(11.75)2]×5.15[(25.75)2+(25.75×20.45)]×22.7\frac{[(34.45)^2-(11.75)^2]×5.15}{[(25.75)^2+(25.75×20.45)]×22.7}​​

Formula Used:

Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}

Solution:

[(34.45)2(11.75)2]×5.15[(25.75)2+(25.75×20.45)]×22.7\frac{[(34.45)^2-(11.75)^2]×5.15}{[(25.75)^2+(25.75×20.45)]×22.7}​​

=[(34.45+11.75)(34.4511.75)]×5.15[(25.75)(25.75+20.45)]×22.7=\frac{[(34.45+11.75)(34.45-11.75)]×5.15}{[(25.75)(25.75+20.45)]×22.7}​​

=[(46.2)(22.7)]×5.15[(25.75)(46.2)]×22.7=\frac{[(46.2)(22.7)]×5.15}{[(25.75)(46.2)]×22.7}​​

=5.1525.75=\frac{5.15}{25.75}​​

=5152575=\frac{515}{2575}​​

=5152575=\frac{515}{2575}​​

=15= \frac{1}{5}​​

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