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The value of 33−52+(2613)2−8+0×9=3^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9 =33−52+(1326​)2−8+0×9= _____​
Question

The value of 3352+(2613)28+0×9=3^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9 = _____​

A.

-3

B.

-5

C.

-4

D.

-2

Correct option is D

Given:

 3352+(2613)28+0×9=3^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9 =

Solution:  

3352+(2613)28+0×93^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9

= 27 - 25 + 4 - 8 + 0 

= 2  +4 - 8  

= -2 



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