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    The value of 33−52+(2613)2−8+0×9=3^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9 =33−52+(1326​)2−8+0×9= _____​
    Question

    The value of 3352+(2613)28+0×9=3^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9 = _____​

    A.

    -3

    B.

    -5

    C.

    -4

    D.

    -2

    Correct option is D

    Given:

     3352+(2613)28+0×9=3^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9 =

    Solution:  

    3352+(2613)28+0×93^3 - 5^2 + (\frac{26}{13})^2 - 8 + 0 \times 9

    = 27 - 25 + 4 - 8 + 0 

    = 2  +4 - 8  

    = -2 



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