The value of  $$\left\{\left(234^5 - 243^8 + \frac{1}{72}\right)^{-8}\right\}^0 + 8$$​​

Correct option is B

Given  :           

 $$\left\{\left(234^5 - 243^8 + \frac{1}{72}\right)^{-8}\right\}^0 + 8$$​                          

Concept Used :

Anything raised to the power of 000 is 111

$$a^0 = 1$$​​

Solution : 

​$$\left\{\left(234^5 - 243^8 + \frac{1}{72}\right)^{-8}\right\}^0 + 8$$​

So, value of 

​$$\left \{\left(234^5 - 243^8 + \frac{1}{72}\right)^{-8}\right\}^0=1$$   $$\because \text{Anything to the power of 0 is 1}$$. 

Now, 

= 1 + 8 

= 9  

Hence option (b) is correct .