​$$\text{The value of } 17^3 - 10^2 + \left( \frac{26}{13} \right)^2 - 12 + 20 \times 12 =$$​​

Correct option is D

Given:

Evaluate $$17^{3}-10^{2}+\left(\frac{26}{13}\right)^{2}-12+20\times12$$​​

Concept Used:

$$\begin{array}{|l|l|}\hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} & [\,], \{\,\}, (\,) \\\hline\text{Orders, of} & ^x \, (\text{power}), \, \sqrt{} \, (\text{root}), \, \text{of} \\\hline\text{Division} & \div \\\hline\text{Multiplication} & \times \\\hline\text{Addition} & + \\\hline\text{Subtraction} & - \\\hline\end{array}$$​

Solution:

$$17^{3}-10^{2}+\left(\frac{26}{13}\right)^{2}-12+20\times12$$​

= 4913 - 100 + 4 - 12 + 240

= 4813 - 8 + 240

= 4805 + 240 = 5045.