The value of $$10 +3 \frac{3}{5}÷[2 \frac{2}{3}÷{(7\frac{ 1}{6}-(2 \frac{1}{2}+\frac{2}{3}))}]$$​ is equal to:

Correct option is A

Solution:
​$$10 +3 \frac{3}{5}÷[2 \frac{2}{3}÷({7\frac{ 1}{6}-(2 \frac{1}{2}+\frac{2}{3}))}] \\\ \\= 10 +\frac{18}{5} ÷[\frac{8}{3}÷({\frac{43}{6}-(\frac{5}{2}+\frac{2}{3}))}] \\\ \\= 10 + \frac{18}{5} ÷[\frac{8}{3}÷{(\frac{43}{6}-(\frac{(15+4)}{6}))}] \\\ \\= 10 + \frac{18}{5}÷[\frac{8}{3}÷{(\frac{43}{6}-(\frac{19}{6}))}] \\\ \\= 10 + \frac{18}{5} ÷[\frac{8}{3}÷{(\frac{(43-19)}{6}}]\\\ \\= 10 +\frac{18}{5} ÷[\frac{8}{3}÷\frac{24}{6}] \\\ \\=10 +\frac{18}{5} ÷[\frac{8}{3}×\frac{6}{24}] \\\ \\=10 +\frac{18}{5}÷\frac{2}{3} \\\ \\=10 +\frac{18}{5}×\frac{3}{2}\\\ \\=10 +\frac{27}{5 }\\\ \\= \frac{(50+27)}{5} =\frac{77}{5}$$​​