The value of $$\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$$​ is :

Correct option is B

Given:

$$\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$$

Formula Used:

a​³ - b³=(a - b) (a² +ab +b²)

Solution:

$$\frac{(0.96)^3-(0.1)^3}{(0.96)^2+0.096+(0.1)^2}$$

=$$\frac{(0.96-0.1)((0.96)^2+0.096+(0.1)^2)}{(0.96)^2+0.096+(0.1)^2}$$

= 0.96 - 0.1= 0.86