The value of $$\frac{[(0.68)^2 + (0.32)^2 + 16 \times 0.0136]}{[(0.68)^3 - (0.32)^3] \div (0.3)^2}$$ is:

Correct option is A

Given:

​$$\frac{[(0.68)^2 + (0.32)^2 + 16 \times 0.0136]}{[(0.68)^3 - (0.32)^3] \div (0.3)^2}$$​​

Formula Used:

​$$a^3 - b^3 = (a-b)(a^2 + b^2 +ab)$$​​

Solution:

​$$\frac{[(0.68)^2 + (0.32)^2 + 16 \times 0.0136]}{[(0.68)^3 - (0.32)^3] \div (0.3)^2}$$​​

​$$\frac{[(0.68)^2 + (0.32)^2 + 0.68 \times 0.32]}{[(0.68-0.32)(0.68)^2 + (0.32)^2 + (0.68)(0.32)] \div (0.3)^2}$$​​

​$$\frac{1}{[(0.68-0.32)] \div (0.3)^2}$$​​

​$$\frac{(0.3)^3}{[(0.36)]}$$​​

$$\frac{0.09}{0.36}$$

$$=\frac{1}{4}$$​

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