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    The two expressions on either side of the equal sign will have the same value if two numbers on the left-hand side are interchanged and two signs on t
    Question

    The two expressions on either side of the equal sign will have the same value if two numbers on the left-hand side are interchanged and two signs on the right-hand side are interchanged. What are those two numbers (not digits) and the two signs?
    4 × 3 ÷ 6 + 2 – 8 = 10 + 2 × 3 ÷ 5 – 18​​

    A.

    2 and 4; + and ×

    B.

    4 and 6; ÷ and ×

    C.

    4 and 8; + and ÷

    D.

    6 and 8; + and -

    Correct option is C

    Given: 4 × 3 ÷ 6 + 2 – 8 = 10 + 2 × 3 ÷ 5 – 18
    Operation preference wiseSymbolBrackets[],,()Orders, of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline\textbf{Operation preference wise} & \textbf{Symbol} \\\hline\text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline \end{array} ​​
    Option A) 2 and 4; + and × 

    2 × 3 ÷ 6 + 4 – 8 = 10 × 2 + 3 ÷ 5 – 18

    2 × 12\frac {1}{2}​ + 4 – 8 = 10 × 2 + 3 ÷ 5 – 18

    (Not integer)
    Option B) 4 and 6; ÷ and ×
    6 × 3 ÷ 4 + 2 – 8 = 10 + 2 ÷ 3 × 5 – 18
    (Not integer)
    ​Option C) 4 and 8; + and ÷
    8 × 3 ÷ 6 + 2 – 4 = 10 ÷  2 × 3 + 5 – 18
    8 × 12\frac{1}{2}​ + 2 – 4 = 5 × 3 + 5 – 18
    4 + 2 – 4 = 15 + 5 – 18
    6 – 4 = 20 – 18
    2 = 2 (Correct)
    Thus, correct option is (c).
    Note: The given condition states that two numbers on the LHS and two signs on the RHS need to be interchanged.​




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