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The top of two towers of heights x and y standing on level ground, subtend angles of 60° and 30° respectively at the midpoint of the line joining thei
Question

The top of two towers of heights x and y standing on level ground, subtend angles of 60° and 30° respectively at the midpoint of the line joining their feet. The value of x : y is:

A.

2 : 1

B.

1 : 2

C.

1 : 3

D.

3 : 1

Correct option is D

Given:

Two towers of heights x and y, subtending angles of 60° and 30° respectively at the midpoint of the line joining their feet.

Concept Used:

Tan function in a right triangle: tanθ=oppositeadjacent\tan \theta = \frac{\text{opposite}}{\text{adjacent}}​​

Let the distance from the midpoint to each tower's base be d. tan60=xd,tan30=yd\tan 60^\circ = \frac{x}{d}, \quad \tan 30^\circ = \frac{y}{d}​​

Values of standard tangents:  tan60=3,tan30=13 \tan 60^\circ = \sqrt{3}, \quad \tan 30^\circ = \frac{1}{\sqrt{3}}  

Solution:

From the given angles,tan60=xd=>x=3dtan30=yd=>y=d3\begin{aligned}&\text{From the given angles,} \\&\tan 60^\circ = \frac{x}{d} \Rightarrow x = \sqrt{3} d \\&\tan 30^\circ = \frac{y}{d} \Rightarrow y = \frac{d}{\sqrt{3}}\end{aligned}​​

Taking the ratio x : y,

xy=3dd3=3×3=3\frac{x}{y} = \frac{\sqrt{3} d}{\frac{d}{\sqrt{3}}} = \sqrt{3} \times \sqrt{3} = 3​​

Thus,

x:y=3:1

Option (d) is right.

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