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    The top of two towers of heights x and y standing on level ground, subtend angles of 60° and 30° respectively at the midpoint of the line joining thei
    Question

    The top of two towers of heights x and y standing on level ground, subtend angles of 60° and 30° respectively at the midpoint of the line joining their feet. The value of x : y is:

    A.

    2 : 1

    B.

    1 : 2

    C.

    1 : 3

    D.

    3 : 1

    Correct option is D

    Given:

    Two towers of heights x and y, subtending angles of 60° and 30° respectively at the midpoint of the line joining their feet.

    Concept Used:

    Tan function in a right triangle: tanθ=oppositeadjacent\tan \theta = \frac{\text{opposite}}{\text{adjacent}}​​

    Let the distance from the midpoint to each tower's base be d. tan60=xd,tan30=yd\tan 60^\circ = \frac{x}{d}, \quad \tan 30^\circ = \frac{y}{d}​​

    Values of standard tangents:  tan60=3,tan30=13 \tan 60^\circ = \sqrt{3}, \quad \tan 30^\circ = \frac{1}{\sqrt{3}}  

    Solution:

    From the given angles,tan60=xd=>x=3dtan30=yd=>y=d3\begin{aligned}&\text{From the given angles,} \\&\tan 60^\circ = \frac{x}{d} \Rightarrow x = \sqrt{3} d \\&\tan 30^\circ = \frac{y}{d} \Rightarrow y = \frac{d}{\sqrt{3}}\end{aligned}​​

    Taking the ratio x : y,

    xy=3dd3=3×3=3\frac{x}{y} = \frac{\sqrt{3} d}{\frac{d}{\sqrt{3}}} = \sqrt{3} \times \sqrt{3} = 3​​

    Thus,

    x:y=3:1

    Option (d) is right.

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