the table gives the marks of two friends Anita and Sunita in various subjects in a semester exam. What is the difference between their percentage of aggregate marks?

Correct option is A

Given:

Marks obtained by Anita:

English: 70/100, French: 50/100, Biology: 45/50, Physics: 30/50

Marks obtained by Sunita:

English: 85/100, French: 90/100, Biology: 40/50, Physics: 25/50

Formula Used:

​$$\text{Aggregate percentage} = \frac{\text{Total Marks Obtained}}{\text{Total Maximum Marks}} \times 100$$​​

Solution:

The total marks obtained by Anita and her aggregate percentage:

​$$\text{Anita\'s total marks} = 70 + 50 + 45 + 30 = 195$$​​

Anita\'s total maximum marks = 100 + 100 + 50 + 50 = 300

Anita\'s aggregate percentage = $$\frac{195}{300} \times 100 = 65\%$$​​

The total marks obtained by Sunita and her aggregate percentage:

​$$\text{Sunita\'s total marks} = 85 + 90 + 40 + 25 = 240$$​​

Sunita's total maximum marks} = 100 + 100 + 50 + 50 = 300

Sunita's aggregate percentage = $$\frac{240}{300} \times 100 = 80\%$$​​

 The difference between their aggregate percentages:

​$$\text{Difference} = 80\% - 65\% = 15\%$$​​

Thus, the difference between their percentage of aggregate marks is 15%.