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The sum of two numbers is 66 and their HCF and LCM are 3 and 315 respectively. The sum of the reciprocals of the numbers will be :
Question

The sum of two numbers is 66 and their HCF and LCM are 3 and 315 respectively. The sum of the reciprocals of the numbers will be :

A.

56315\frac{56}{315}​​

B.

22315\frac{22}{315}​​

C.

66315\frac{66}{315}​​

D.

3315\frac{3}{315}​​

Correct option is B

Given:

Sum of two numbers = 66

HCF = 3, LCM = 315

Formula Used:

Product of two numbers = HCF × LCM

Solution:

Sum of reciprocals = 1a+1b=a+bab \frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab}​​

ab = HCF × LCM = 3 × 315 = 945

a + b = 66

Now, Putting values;

a+bab=66945=22315\frac{a + b}{ab} = \frac{66}{945} = \frac{22}{315}​​

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