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    The sum of two numbers is 66 and their HCF and LCM are 3 and 315 respectively. The sum of the reciprocals of the numbers will be :
    Question

    The sum of two numbers is 66 and their HCF and LCM are 3 and 315 respectively. The sum of the reciprocals of the numbers will be :

    A.

    56315\frac{56}{315}​​

    B.

    22315\frac{22}{315}​​

    C.

    66315\frac{66}{315}​​

    D.

    3315\frac{3}{315}​​

    Correct option is B

    Given:

    Sum of two numbers = 66

    HCF = 3, LCM = 315

    Formula Used:

    Product of two numbers = HCF × LCM

    Solution:

    Sum of reciprocals = 1a+1b=a+bab \frac{1}{a} + \frac{1}{b} = \frac{a + b}{ab}​​

    ab = HCF × LCM = 3 × 315 = 945

    a + b = 66

    Now, Putting values;

    a+bab=66945=22315\frac{a + b}{ab} = \frac{66}{945} = \frac{22}{315}​​

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