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The sum of two numbers is 20 and the product of their LCM and HCF is 96. Then the sum of squares of these numbers is equal to:
Question

The sum of two numbers is 20 and the product of their LCM and HCF is 96. Then the sum of squares of these numbers is equal to:

A.

208

B.

582

C.

2308

D.

1033

Correct option is A

Given:
Sum of the two numbers = 20
Product of their LCM and HCF = 96
Formula:
For two positive integers:
Product of two numbers = LCM × HCF
Also,
a² + b² = (a + b)² − 2ab
Solution:
Let the two numbers be a and b.
Since,
LCM × HCF = 96
Therefore,
ab = 96
Given,
a + b = 20
Now,
a² + b²
= (a + b)² − 2ab
= 20² − 2 × 96
= 400 − 192
= 208
Hence, the correct answer is Option (a) 208.

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