The sum of three consecutive multiples of 8 is 2424, find the largest one.

Correct option is D

Given:  

Sum of three consecutive multiple of 8 = 2424 

Solution:

Let first multiple = 8x 

Second multiple = 8(x+1)

Third multiple = 8(x + 2) 

According to the question 

8x + 8x +  8 + 8x + 16 = 2424 

24x = 2424 - 24 

24x = 2400 

x = 100 

Then three consecutive multiple of 8 of which sum is 2424 ..

First = $$100\times 8 = 800$$ 

Second = $$8\times(100+1) = 808$$ 

Third = $$8\times(100+2)= 816$$​​

Largest one = 816