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    The speed of a stream is 9 km/h. A boat can go 28 km downstream and 20 km upstream in 8 hours. What is the speed (in km/h) of the boat in still water?
    Question

    The speed of a stream is 9 km/h. A boat can go 28 km downstream and 20 km upstream in 8 hours. What is the speed (in km/h) of the boat in still water?

    A.

    14

    B.

    9

    C.

    12

    D.

    6

    Correct option is C

    Given:
    Speed of the stream = 9 km/h.
    Downstream distance = 28 km.
    Upstream distance = 20 km.
    Total time = 8 hours.
    Formula Used:
    Downstream speed = Speed of boat in still water + Speed of stream.
    Upstream speed = Speed of boat in still water - Speed of stream.
    Time=DistanceSpeed\text{Time} = \dfrac{\text{Distance}}{\text{Speed}}​​
    Solution:
    Let the speed of the boat in still water be x km/h.
    Downstream speed = x + 9.
    Upstream speed = x - 9.
    Time taken to travel downstream = 28x+9\dfrac{28}{x+9}​​

    Time taken to travel upstream  = 20x9\dfrac{20}{x-9}​​
    Total time = Time downstream + Time upstream = 8 hours.
    =>28x+9+20x9=8=>28(x9)+20(x+9)(x+9)(x9)=8=>28x252+20x+180x281=8=>48x72x281=8=>48x72=8(x281)=>48x72=8x2648=>8x248x576=0=>x26x72=0=>x212x+6x72=0=>x(x12)+6(x12)=0=>(x12)(x+6)=0=>x=12 or x=6\begin{aligned}&\Rightarrow \dfrac{28}{x+9} + \dfrac{20}{x-9} = 8 \\&\Rightarrow \dfrac{28(x-9) + 20(x+9)}{(x+9)(x-9)} = 8 \\&\Rightarrow \dfrac{28x - 252 + 20x + 180}{x^2 - 81} = 8 \\&\Rightarrow \dfrac{48x - 72}{x^2 - 81} = 8 \\&\Rightarrow 48x - 72 = 8(x^2 - 81) \\&\Rightarrow 48x - 72 = 8x^2 - 648 \\&\Rightarrow 8x^2 - 48x - 576 = 0 \\&\Rightarrow x^2 - 6x - 72 = 0 \\&\Rightarrow x^2 - 12x + 6x - 72 = 0 \\&\Rightarrow x(x-12) + 6(x-12) = 0 \\&\Rightarrow (x-12)(x+6) = 0 \\&\Rightarrow x = 12 \; \text{or} \; x = -6\end{aligned}​​
    Since speed cannot be negative, x = 12 km/h.
    The speed of the boat in still water is 12 km/h.

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