The ratio between the fourth proportional of 7, 5 and 3 to the third proportional of 7 and 13 is:

Correct option is B

Formula Used:
Fourth proportional of a, b, c is bc/a
Third proportional to x, y is y2/x
Solution:

​$$\Rightarrow \text{Fourth proportional to } 7, 5 \text{ and } 3 = \frac{5 \times 3}{7} = \frac{15}{7} \\ \Rightarrow \text{Third proportional of } 7, 13 = \frac{13^2}{7} \\ \therefore \text{Required ratio} = \frac{\frac{15}{7}}{\frac{132}{7}} = \frac{15}{169} = 15 \colon 169$$​​