The product of $$\sqrt2$$​ and $$\sqrt3$$​ is:

Correct option is D

Given:

The product of $$\sqrt2$$​ and $$\sqrt3$$​ is:

Concept Used:

An irrational number is a number that cannot be expressed as a fraction $$\frac pq$$, where p and q are integers and q is not equal to 0.

Solution:

$$\sqrt 2\times\sqrt 3 =\sqrt 6$$

$$\sqrt 6$$​ is an irrational number.