The Poisson's ratio of a stable, isotropic, linear elastic material cannot be less than:

Correct option is C

​$$\text{The relations between elastic constants and Poisson’s ratio } \mu \text{ are given by:} \\[6pt]E = 2G(1 + \mu) \qquad \text{(i)} \\[6pt]E = 3K(1 - 2\mu) \qquad \text{(ii)} \\[10pt]\text{Since elastic constants cannot be negative,} \\[4pt]\text{From (i):} \\[4pt]1 + \mu \ge 0 \Rightarrow \mu \ge -1 \\[8pt]\text{From (ii):} \\[4pt]1 - 2\mu \ge 0 \Rightarrow \mu \le 0.5 \\[10pt]\therefore \ \text{The range of Poisson’s ratio } (\mu) \text{ for any material is:} \\[6pt]-1 < \mu < 0.5 \\[10pt]\text{In practice, the value of } \mu \text{ generally lies between } 0 \text{ and } 0.5.$$​​