The minimum value of the quadratic function $$f(x) = 3x^{2} − 6x + 5$$​ is:

Correct option is B

Given:
​$$f(x) = 3x^{2} − 6x + 5$$​​
Formula used:
For $$ax^{2} + bx + c$$​, minimum value = $$\frac{4ac − b^{2}}{4a}$$​​
Solution:
Here $$a = 3, b = −6, c = 5$$​​
Minimum value
​$$= \frac{4(3)(5) − (−6)^{2}}{4(3)}\\[2pt]= \frac{60 − 36}{12}\\[2pt]= \frac{24}{12}\\[2pt]= 2$$​​
The correct answer is (b) 2.