The maximum distance of the point (10, 7) from the circle $$x^{2} + y^{2} − 4x − 2y − 20 = 0$$​ is:

Correct option is B

Given:
Point P = (10, 7)
Circle: $$x^{2} + y^{2} − 4x − 2y − 20 = 0$$​​
​Formula used:
Maximum distance from a point to a circle = OP + r
where O is the center of the circle and r is the radius.
Solution:
Rewrite the circle in standard form:
​$$(x − 2)^{2} + (y − 1)^{2} = 25$$​​
Center O = (2, 1)
Radius r = 5
Distance OP:
​$$OP = \sqrt{(10 − 2)^{2} + (7 − 1)^{2}}= \sqrt{8^{2} + 6^{2}}= \sqrt{64 + 36}= 10$$​​
Maximum distance = OP + r
= 10 + 5
= 15
The correct answer is (d) 15.
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