The length of a rectangle is 12 cm and the side of a square is 14 cm less than the sum of the length and breadth of the rectangle. If the perimeter of the rectangle is 16 cm more than the perimeter of the square, then find the breadth of the rectangle.

Correct option is C

Let the breadth of the rectangle be ‘b’ cm
And side of the square = ((12+b)-14) cm
ATQ,
2(12+b)-4((12+b)-14)=16
24+2b-4(b-2)=16
24+2b-4b+8=16
32-2b=16
2b=16
b=8