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The length, breadth and height of a cuboid are in ratio of 3 : 4 : 5. If the volume of the cuboid is 1620 m3m^3m3​, find the total surface area of the
Question

The length, breadth and height of a cuboid are in ratio of 3 : 4 : 5. If the volume of the cuboid is 1620 m3m^3​, find the total surface area of the cuboid.

A.

646 m2m^2​​

B.

846m2846 m^2​​

C.

423 m2m^2​​

D.

712 m2m^2​​

Correct option is B

Given:
Volume of cuboid = 1620 m^3
Ratio of length breadth and height of cuboid = 3:4:5
Formula Used:
Volume of cuboid= lbh
Total surface area of tank = 2 (lb+bh+lh)
Solution:
Let the ratio be 3x 4x 5x
The(3x)(4x)(5x)=1620m3 60x3=1620 x3=27 x=3The (3x)(4x)(5x)=1620m^3 \\\ \\60 x^3 = 1620 \\\ \\x^3 = 27 \\\ \\x=3​​
Length =3x= 9m
Breadth =4x= 12m
Height =5x = 15m
Total surface area = 2(9×12+12×15+15×9)=846m2 2 (9\times12+12\times15+15\times9) =846m^2​​

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