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    The length, breadth and height of a cuboid are in ratio of 3 : 4 : 5. If the volume of the cuboid is 1620 m3m^3m3​, find the total surface area of the
    Question

    The length, breadth and height of a cuboid are in ratio of 3 : 4 : 5. If the volume of the cuboid is 1620 m3m^3​, find the total surface area of the cuboid.

    A.

    646 m2m^2​​

    B.

    846m2846 m^2​​

    C.

    423 m2m^2​​

    D.

    712 m2m^2​​

    Correct option is B

    Given:
    Volume of cuboid = 1620 m^3
    Ratio of length breadth and height of cuboid = 3:4:5
    Formula Used:
    Volume of cuboid= lbh
    Total surface area of tank = 2 (lb+bh+lh)
    Solution:
    Let the ratio be 3x 4x 5x
    The(3x)(4x)(5x)=1620m3 60x3=1620 x3=27 x=3The (3x)(4x)(5x)=1620m^3 \\\ \\60 x^3 = 1620 \\\ \\x^3 = 27 \\\ \\x=3​​
    Length =3x= 9m
    Breadth =4x= 12m
    Height =5x = 15m
    Total surface area = 2(9×12+12×15+15×9)=846m2 2 (9\times12+12\times15+15\times9) =846m^2​​

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