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The LCM of 23×32×5, 22×52×72^3×3^2×5, \ 2^2×5^2×723×32×5, 22×52×7​ and 33×52×723^3×5^2×7^233×52×72​ is:
Question

The LCM of 23×32×5, 22×52×72^3×3^2×5, \ 2^2×5^2×7​ and 33×52×723^3×5^2×7^2​ is:

A.

23×34×52×72^3×3^4×5^2×7​​

B.

23×32×53×722^3×3^2×5^3×7^2​​

C.

23×32×5×732^3×3^2×5×7^3​​

D.

23×33×52×722^3×3^3×5^2×7^2​​

Correct option is D

given:

23×32×5,22×52×72^3×3^2×5,2^2×5^2×7  and 33×52×723^3×5^2×7^2

Solution:

​We have been given three expressions representing three numbers as the product of their prime factors.

23×32×52^3×3^2×5

=22×52×7= 2^2×5^2×7

=33×52×72= 3^3×5^2×7^2

​​We know that LCM is the product of maximum frequencies of all the integers(positive) involved in all prime factorizations.

LCM = 23×33×52×722^3×3^3×5^2×7^2

Thus, correct option is (d)

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