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    The largest number that will divide 789, 861, and 1069 leaving the remainders 7, 11, and 15 respectively is:
    Question

    The largest number that will divide 789, 861, and 1069 leaving the remainders 7, 11, and 15 respectively is:

    A.

    17

    B.

    51

    C.

    34

    D.

    85

    Correct option is C

    Given:

    When dividing:
    789 → remainder 7
    861 → remainder 11
    1069 → remainder 15

    Concept used:
    If a number leaves different remainders, subtract those remainders from each number first.
    Then find the HCF (highest common factor) of the resulting numbers.

    Solution:
    789 − 7 = 782
    861 − 11 = 850
    1069 − 15 = 1054

    Now find HCF of 782, 850, 1054

    850 − 782 = 68
    1054 − 850 = 204

    HCF(782, 850, 1054) = HCF(68, 204)

    204 ÷ 68 = 3 exactly → remainder 0

    So, HCF = 68

    Now check given options: 68 not listed, but 68 = 34 × 2
    → 34 divides all numbers too.

    Thus, largest number = 34

    Correct answer is (c) 34.

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