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The L.C.M of two numbers is 12 times their H.C.F. The sum of H.C.F. and L.C.M is 403. If one number is 93 , find the other.
Question

The L.C.M of two numbers is 12 times their H.C.F. The sum of H.C.F. and L.C.M is 403. If one number is 93 , find the other.

A.

124

B.

128

C.

134

D.

None of these

Correct option is A

Given:

1. The LCM of two numbers is 12 times their HCF.
2. The sum of HCF and LCM is 403.
3. One of the numbers is 93.

Formula Used:

1. HCF ×\times LCM = Product of the two numbers
2. The LCM is given as 12 ×HCF\times \text{HCF}​ 

Solution:

1. Let the HCF of the numbers be x .
Then, LCM = 12x .

2. From the problem, HCF+LCM\text{HCF} + \text{LCM}​ = 403 :

x + 12x = 403

13x = 403 x=31\implies x = 31​​

So, HCF=31andLCM=12×31\text{HCF} = 31 and \text{LCM} = 12 \times 31​ = 372 .

3. Using the formula HCF×LCM=Product of the two numbers\text{HCF} \times \text{LCM} = \text{Product of the two numbers}​ :

31×372=93×Other number31 \times 372 = 93 \times \text{Other number}​​


11532=93×Other number11532 = 93 \times \text{Other number}​​


Other number=1153293=124\text{Other number} = \frac{11532}{93} = 124​​

Final Answer:

The other number is 124 .

**Option A: 124**

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