Question

​The inverse of the matrix A=(11313−3−2−4−4)A=\left($$\begin{array}{ccc}1$$ & 1 & 3 \1 & 3 & -3 \-2 & -4 & -$$4\end{array}$$ight)A=​11−2​13−4​3−3−4​​​ is:​

Accepted Answer

A

Answer

​(311.5−1.25−0.25−0.75−0.25−0.25−0.25)\left($$\begin{array}{ccc}3$$ & 1 & 1.5 \-1.25 & -0.25 & -0.75 \-0.25 & -0.25 & -0.$$25\end{array}$$ight)​3−1.25−0.25​1−0.25−0.25​1.5−0.75−0.25​​​​

Answer

​(311.5−1.50−0.25−0.75−0.25−0.25−0.25)\left($$\begin{array}{ccc}3$$ & 1 & 1.5 \-1.50 & -0.25 & -0.75 \-0.25 & -0.25 & -0.$$25\end{array}$$ight)​3−1.50−0.25​1−0.25−0.25​1.5−0.75−0.25​​​​

Answer

​(311.5−1.25−0.75−0.25−0.25−0.25−0.25)\left($$\begin{array}{ccc}3$$ & 1 & 1.5 \-1.25 & -0.75 & -0.25 \-0.25 & -0.25 & -0.$$25\end{array}$$ight)​3−1.25−0.25​1−0.75−0.25​1.5−0.25−0.25​​​​

Answer

​(311.5−1.25−0.25−0.75−0.25−0.75−0.25)\left($$\begin{array}{ccc}3$$ & 1 & 1.5 \-1.25 & -0.25 & -0.75 \-0.25 & -0.75 & -0.$$25\end{array}$$ight)​3−1.25−0.25​1−0.25−0.75​1.5−0.75−0.25​​​​

The inverse of the matrix $A=\left(\begin{array}{ccc}1 & 1 & 3 \\1 & 3 & -3 \\-2 & -4 & -4\end{array}\right)$ is:

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.25 & -0.75 \\-0.25 & -0.25 & -0.25\end{array}\right)$

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.50 & -0.25 & -0.75 \\-0.25 & -0.25 & -0.25\end{array}\right)$

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.75 & -0.25 \\-0.25 & -0.25 & -0.25\end{array}\right)$

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.25 & -0.75 \\-0.25 & -0.75 & -0.25\end{array}\right)$

Correct option is A

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Similar Questions

​The inverse of the matrix A=(11313−3−2−4−4)A=\left(\begin{array}{ccc}1 & 1 & 3 \\1 & 3 & -3 \\-2 & -4 & -4\end{array}\right)A=​11−2​13−4​3−3−4​​​ is:​

​(311.5−1.25−0.25−0.75−0.25−0.25−0.25)\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.25 & -0.75 \\-0.25 & -0.25 & -0.25\end{array}\right)​3−1.25−0.25​1−0.25−0.25​1.5−0.75−0.25​​​​

​(311.5−1.50−0.25−0.75−0.25−0.25−0.25)\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.50 & -0.25 & -0.75 \\-0.25 & -0.25 & -0.25\end{array}\right)​3−1.50−0.25​1−0.25−0.25​1.5−0.75−0.25​​​​

​(311.5−1.25−0.75−0.25−0.25−0.25−0.25)\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.75 & -0.25 \\-0.25 & -0.25 & -0.25\end{array}\right)​3−1.25−0.25​1−0.75−0.25​1.5−0.25−0.25​​​​

​(311.5−1.25−0.25−0.75−0.25−0.75−0.25)\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.25 & -0.75 \\-0.25 & -0.75 & -0.25\end{array}\right)​3−1.25−0.25​1−0.25−0.75​1.5−0.75−0.25​​​​

Correct option is A

Access ‘AAI JE ATC’ Mock Tests with

Access ‘AAI JE ATC’ Mock Tests with

Similar Questions

The inverse of the matrix $A=\left(\begin{array}{ccc}1 & 1 & 3 \\1 & 3 & -3 \\-2 & -4 & -4\end{array}\right)$ is:

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.25 & -0.75 \\-0.25 & -0.25 & -0.25\end{array}\right)$

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.50 & -0.25 & -0.75 \\-0.25 & -0.25 & -0.25\end{array}\right)$

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.75 & -0.25 \\-0.25 & -0.25 & -0.25\end{array}\right)$

$\left(\begin{array}{ccc}3 & 1 & 1.5 \\-1.25 & -0.25 & -0.75 \\-0.25 & -0.75 & -0.25\end{array}\right)$