arrow
arrow
arrow
The infinite series 12+222+323+⋯+n2n+⋯\frac{1}{2} + \frac{2}{2^2} + \frac{3}{2^3} + \cdots + \frac{n}{2^n} + \cdots21​+222​+233​+⋯+2nn​+⋯is​
Question

The infinite series 12+222+323++n2n+\frac{1}{2} + \frac{2}{2^2} + \frac{3}{2^3} + \cdots + \frac{n}{2^n} + \cdotsis​

A.

divergent

B.

oscillatory

C.

convergent

D.

not bounded.

Correct option is C

Solution:

Given series: S=n=1n2nWe use the identity: n=1nrn=r(r1)2,for r>1Here, r=2=>n=1n2n=2(21)2=21=2The series is convergent and its sum is 2\begin{aligned}&\text{Given series: } S = \sum_{n=1}^{\infty} \frac{n}{2^n} \\&\text{We use the identity: } \sum_{n=1}^{\infty} \frac{n}{r^n} = \frac{r}{(r - 1)^2}, \quad \text{for } r > 1 \\&\text{Here, } r = 2 \Rightarrow \sum_{n=1}^{\infty} \frac{n}{2^n} = \frac{2}{(2 - 1)^2} = \frac{2}{1} = 2 \\&\therefore \text{The series is convergent and its sum is } \boxed{2}\end{aligned}

​​

Free Tests

Free
Must Attempt

UPTET Paper 1: PYP Held on 23rd Jan 2022 (Shift 1)

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English
Free
Must Attempt

UPTET Paper 2 Social Science : PYP Held on 23rd Jan 2022 (Shift 2)

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English
Free
Must Attempt

UPTET Paper 2 Maths & Science : PYP Held on 23rd Jan 2022 (Shift 2)

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English
test-prime-package

Access ‘WB SLST’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
354k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow